(x+1)*(x^2+2x+1)=0

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Solution for (x+1)*(x^2+2x+1)=0 equation: 


Simplifying
(x + 1)(x2 + 2x + 1) = 0

Reorder the terms:
(1 + x)(x2 + 2x + 1) = 0

Reorder the terms:
(1 + x)(1 + 2x + x2) = 0

Multiply (1 + x) * (1 + 2x + x2)
(1(1 + 2x + x2) + x(1 + 2x + x2)) = 0
((1 * 1 + 2x * 1 + x2 * 1) + x(1 + 2x + x2)) = 0
((1 + 2x + 1x2) + x(1 + 2x + x2)) = 0
(1 + 2x + 1x2 + (1 * x + 2x * x + x2 * x)) = 0
(1 + 2x + 1x2 + (1x + 2x2 + x3)) = 0

Reorder the terms:
(1 + 2x + 1x + 1x2 + 2x2 + x3) = 0

Combine like terms: 2x + 1x = 3x
(1 + 3x + 1x2 + 2x2 + x3) = 0

Combine like terms: 1x2 + 2x2 = 3x2
(1 + 3x + 3x2 + x3) = 0

Solving
1 + 3x + 3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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